The solution set for 7q2 − 28 = 0 is

2 and -2

Step-by-step explanation:

● 7q^2 -28 = 0

Add 28 to both sides

● 7q^2-28+28 = 28

● 7q^2 = 28

Divide both sides by 7

●7q^2/7 = 28/7

● q^2 = 4

You can write directly q= 2 or q= -2

To understand it use the absolute value.

● |q| = 2

● q = 2 or q = -2

The solutions are {2, -2}

5/6

step-by-step explanation:

if i remember correctly with perpendicular stuff you just take away the negative

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.