Find the area ratio of a regular octahedron and a tetrahedron regular, knowing that the diagonal of the octahedron is equal to height of the tetrahedron.

Step-by-step explanation:

The area of a regular octahedron is given by:

area = . Let a is the length of the edge (diagonal).

area =

Given that the diagonal of the octahedron is equal to height (h) of the tetrahedron i.e.

a = h, where h is the height of the tetrahedron and a is the diagonal of the octahedron. Let the edge of the tetrrahedron be e. To find the edge of the tetrahedron, we use:

The area of a tetrahedron is given by:

area = =

The ratio of area of regular octahedron to area tetrahedron regular is given as:

Ratio =

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

8y^50

step-by-step explanation: