Select the best answer for the question. 2. Find the sum of the first 8 terms of a geometric series in which a1 = 3 and r= 2.

Work Shown:

a = 3 is the first term

r = 2 is the common ratio

Sn = a*(1-r^n)/(1-r) ... sum of the first n terms

S8 = 3*(1-2^8)/(1-2) ... sum of the first 8 terms

S8 = 3*(-255)/(-1)

S8 = 765

We can generate the first 8 terms to get 3, 6, 12, 24, 48, 96, 192, 384. Each new term is found by multiplying the previous one by 2.

Then add them up to get 3+6+12+24+48+96+192+384 = 765. We get the same result.

10 cm

step-by-step explanation:

if the polygon is a rectangle, then the perimeter is x+x+y+y. using the values that you gave, the perimeter is 3+3+2+2=10cm.

square root

step-by-step explanation: