Assume that the random variable X is normally distributed, with mean p = 100 and standard deviation o = 15. Compute the probability P(X > 112).

P(X > 112) = 0.21186.

Step-by-step explanation:

We are given that the random variable X is normally distributed, with mean = 100 and standard deviation = 15.

Let X = a random variable

The z-score probability distribution for the normal distribution is given by;

                               Z  =    ~ N(0,1)

where, = population mean = 100

            = standard deviaton = 15

Now, the probability that the random variable X is greater than 112 is given by = P(X > 112)

      P(X > 112) = P( > ) = P(Z > 0.80) = 1- P(Z 0.80)

                                                       = 1 - 0.78814 = 0.21186  

The above probability is calculated by looking at the value of x = 0.80 in the z table which has an area of 0.78814.

1,8,15,22,29,36,43,50

step-by-step explanation:

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.