If m(2x−3)+n(x+1)=5x for all real numbers x, where m and n are constants, what is the value of m?

m = 1

Step-by-step explanation:

From the question given,

m(2x − 3) + n(x + 1) = 5x for all real numbers x.

Since x is a real number, we can obtain the value of m as follow:

Let x = 1

m(2x − 3) + n(x + 1) = 5x

m(2×1 − 3) + n(1 + 1) = 5×1

m(2 – 3) + n(2) = 5

m(– 1) + n(2) = 5

– m + 2n = 5 (1)

Let x = 2

m(2x − 3) + n(x + 1) = 5x

m(2×2 − 3) + n(2 + 1) = 5×2

m(4 – 3) + n(3) = 10

m(1) + n(3) = 10

m + 3n = 10 (2)

– m + 2n = 5 (1)

m + 3n = 10 (2)

Solve by elimination method

Add equation 1 and 2

– m + 2n = 5

+ (m + 3n = 10)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

5n = 15

Divide both side by 5

n = 15/5

n = 3

Substitute the value of n into any of the equation to obtain the value of m. Here, we shall substitute n into equation 2.

m + 3n = 10

m + 3(3) = 10

m + 9 = 10

Collect like terms

m = 10 – 9

m = 1

Therefore, the value of m is 1

the answer to the expression is 83

d. all of the above

step-by-step explanation: