What is an equation of the line that passes through the point (-2, -3) and is parallel to the line 5x + 2y = 14?

2y + 5x + 16 = 0

Step-by-step explanation:

To solve this you need to understand the principle/ conditions for parallelism and perpendicularity.

for two lines to be parallel to each other, their gradients or slopes (m) must be equal, that is  m₁ = m₂

Now from the given equation,

5x + 2y = 14 , we need to rearrange it to conform to the equation of a straight line so that the gradient could be established. ie

y = mx + c where m is the gradient

 2y = -5x  + 14

   y = -5x/2  + 14/2

   y = ⁻⁵ˣ/₂  + 7 , therefore , m₁ = ⁻⁵/₂ and m₂ = ⁻⁵/₂ ( parallelism Rule )

The next step is to find the value of C using the coordinate ( -2, -3 )

  -3 = ⁻⁵/₂ ˣ ⁻² + C,

  -3 =  ¹⁰/₂  + C

  -3 =  5 + C

   C = -8.

Now to find the equation of the line that passed through the coordinate

  y = mx + c

  y = ⁻⁵ˣ/₂  - 8

  2y = -5x - 16

  2y + 5x + 16 = 0.

its a straight line parallel to the time axis

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet