Recall that 0°c = 32°f and 100°c =212°f
•using x for degrees celsius and y for degrees fahrenheit, find an equation of the line passing through (0,32) and (100,212).
•what is the slope of the line? explain what the y-intercept means in terms of degrees celsius and degrees fahrenheit.
•what is the y-intercept of the line? explain what the y-intercept means in terms of degrees celsius and degrees fahrenheit.

(0,32)(100,212)
slope = (y2 - y1) / (x2 - x1)
slope(m) = (212 - 32) / (100 - 0) = 180/100 = 9/5 (or 1.8)
so the slope of the line is 9/5...this means that a farenheit degree change is equivalent to a celsius change of 9/5(or 1.8 degrees)

now we find the y int.
y = mx + b
slope(m) = 9/5
(0,32)..x = 0 and y = 32
now we sub and find b, the y int
32 = 9/5(0) + b
32 = b
so ur y int is 32...this means that when celsius temp starts at 0, farenheit temp is 32 degrees

Ujjg