How do you find slopes at specific points with tangent functions??

Step-by-step explanation:

The slope of the tangent line of a function f(x) is the derivative, f'(x).

Here, we can use exponent rule to find the derivatives:

If y = xⁿ, then y' = nxⁿ⁻¹.

7. g(x) = x²

g'(x) = 2x

g'(2) = 4

8. g(x) = x² − 4x

g'(x) = 2x − 4

g'(1) = -2

9. g(x) = 5/(x + 3)

g(x) = 5 (x + 3)⁻¹

g'(x) = -5 (x + 3)⁻²

g'(-2) = -5

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4