A man drives from home at 10.45 to the airport which is 325 km away. He travels at an average speed of 50km/h. a) Find his arrival time at the airport. b)After sending of his friend, the man drives back at 18 35 and arrives home at 23 10. Write down the time taken for the return journey.

We have,

Finding time taken by the man,

⇛ Average speed = Total Distance/Total time

⇛ Total time = Total Distance/Average speed

⇛ Total time = 325 km/50 km/h

⇛ Total time = 6.5 h (6 hrs 30 mins)

(a) Total Time duration,

⇛ Total Time = Reaching Time - Departing time

⇛ 6.5 h = Reaching Time - 10 : 45 hours

⇛ Reaching Time = 17 : 15 hours ( 5 : 15 pm)

(b) Finding time taken in return,

Total time duration,

⇛ Total Time = Reaching Time - Departing time

⇛ Total Time = 23 : 10 hours - 18 : 35 hours

⇛ Total Time = 22 : 70 hours - 18 : 35 hours

⇛ Total time = 4 : 35 hours

☕ Hence, solved !!

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we have three similar triangles, because each has a right angle and shares an angle.   let's write the angles in order: opposite to short leg, long leg, hypotenuse.

cab similar to bad similar to cbd

or as ratios,

ca: ab: cb = ba: ad: bd = cb: bd: cd

we also know

ac = ad + cd

(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd

(ad+cd)/cb=cb/cd

we have cb=6, ad=5 and seek x=cd.

we reject the negative root and conclude x=4

answer: 4

1.30

step-by-step explanation: