A line passes through the point (-6, 8) and has a slope of 3
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Write an equation in slope-intercept form for this line.

y=3x+26

Step-by-step explanation:

We can start by writing this line in point-slope form.

Point-slope form is:

y-y1=m(x-x1)

This is where m is the slope

x1 and y1 are the x and y coordinates of a given point on a line.

With the given info, we are able to write the following equation:

y-8=3(x-(-6))

y-8=3(x+6)

We can now simplify that to slope-intercept form which is y=mx+b

m is slope and b is y-intercept in this form.

y-8=3(x+6)

Distribute

y-8=3x+18

Add 8 to both sides.

y=3x+26

y = 3x + 26

Step-by-step explanation:

Plug in the slope and the given point into the equation, y = mx + b

Solve for b (y intercept)

8 = 3(-6) + b

8 = -18 + b

26 = b

Now, plug this into the equation with the slope:

y = 3x + 26 will be the equation

x is variable or an unknown value to find

example:

2x = 5 which means x = 3