A golfer recorded the following scores for each of four rounds of golf: 86, 81, 87, 82. The mean of the scores is 84. What is the sum of the squared deviations of the scores from the mean?

The sum of the squared deviations of the scores from the mean is 26.

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Thus:

The sum of the squared deviations of the scores from the mean is 26.

A similar problem is given at link

26

Step-by-step explanation:

The mean of a set of number is the average the set of number, it is the ratio of the total sum of the terms to the sum of terms.

The standard deviation is the variation of a set of numbers to their mean. A low standard deviation means the value are close to the mean and a high standard deviation means the values are far from the mean. The standard deviation is given as:

Given the numbers:

86, 81, 87, 82. mean = μ = 84

Sum of squared deviations = 26

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

22

step-by-step explanation: