Help please? 10 points

  277 cm^2

Step-by-step explanation:

Two of the triangular faces will have areas of ...

  A = 1/2bh = (1/2)(8 cm)(11 cm) = 44 cm^2

and the other two will have areas of ...

  A = 1/2bh = (1/2)(9 cm)(13 cm) = 58.5 cm^2

The base will have an area of ...

  A = LW = (9 cm)(8 cm) = 72 cm^2

So, the total area will be ...

  2(44 cm^2) +2(58.5 cm^2) +72 cm^2 = 277 cm^2

Comment on the problem

You could not actually build this pyramid. The height of the peak above the 8-cm edges must be ...

  √(11^2 -(4.5)^2) = 10.04 cm

The height of the peak above the 9-cm edges must be ...

  √(13^2 -4^2) = 12.37 cm.

The peak cannot be in two places at once. This geometry is impossible.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet