Find the value of x if PQ = x^2 + 3, QR = 4 + 2x, and PR = 15 if Q is between P and R.

x=2

Step-by-step explanation:

PQ+QR=PR

=x^2+3+4+2x=15

=x^2+2x+7=15

=x^2+2x+7-15=0

=x^2+2x-8=0. (quadratic equation)

=(x+4)(x-2)=0. (factorise)

=x+4=0 or x-2=0

x=-4 or 2

we take x to be the positive value which is

x=2

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.

abde or 1,2,4, 5 is the answer

step-by-step explanation: