Which equation would best represent the situation below using only width as the unknown? The top of the John Hancock Building is a rectangle whose length is 60 ft more than the width. The perimeter is 520 feet.
4(W + 60) = 520
2W + 60 = 520
2W - 60 + 2W = 520
2(W + 60) + 2W = 520

2(w+60) + 2w= 520

perimeter of a rectangle = 2(length)+2(width)
length=w+60ft
width=w
perimeter=520ft
520ft=2(w+60)+2w

I’m not so sure about this one.

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm