Carmen suele ir a la biblioteca de su barrio cada 28 días, Rafael cada 25 y Teresa cada 22. El día 12 de septiembre se encuentran los 3 amigos. ¿Qué día volverán a coincidir?

Responder:

7.700

Explicación paso a paso:

Dado que:

Carmen va a la biblioteca cada 28 días

Rafael va a la biblioteca cada 25

Theresa cada 22 días.

Si todos se reunieron el 12 de septiembre, ¿cuándo volverán a reunirse?

Para obtener la fecha de su próxima reunión, multa el mínimo común múltiplo de los diferentes días en que Theresa, Rafael y Carmen van a la biblioteca

28__25__22

__2_14__25___11

__2_7__25___11

__5_7__511

__5_7__111

__7_1__111

_ 11_1__1 1

Por lo tanto, el múltiplo común más bajo:

(2 * 2 * 5 * 5 * 7 * 11) = 7700

Por lo tanto, todos se volverán a encontrar en el nido 7.700 días

answer: idk

step-by-step explanation:

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺