Help me answer Kendal is waiting at a crosswalk 540 meters away from the library. She begins riding her bike toward the library and then passes the library at a constant rate of 6meters/second.

Kendal will be 60 meters away from the library after second and agin after seconds.

Kendal will be 60 meters away from the library after 80 seconds and again after 100 seconds.

Step-by-step explanation:

6s -540 = 60 or 6s - 540 = -60

First equation

addition property of equality: 6s -540 + 540 = 60 + 540

simplify: 6s = 600

division property of equality: 6s/6 = 600/6

simplify: s = 100

Second equation

addition property of equality: 6s -540 + 540  = -60 + 540

simplify: 6s = 480

division property of equality: 6s/6 = 480/6

simplify: s = 80

Kendal will be 60 meters away from the library after 80 seconds and again after 100 seconds.

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

idk

step-by-step explanation: