[B] 19.5, 160.5
Mathematics, 15.10.2020 01:01 kayla942783
19. Solve the equation 3cos x = 8tan x, between Oº and 360°
O [A] 3.99,5.44
[B] 19.5, 160.5
[C] 0.197,3.34
O [D] 1.89, 5.03
Answers: 1
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The point (-7, -24) is on the terminal ray of angle 0 which is in standard position. a student found the six trigonometric values for angle e. the student's answers are shown. which value(s) are incorrect? sin(8) cos(8) 24 tan(0) sin(0)=25 cos(0) -- tan(ⓡ) - - 24 csc(o)=2 sec(0) --25 cot(6) - za csc(o) sec(0) cot(0) done
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19. Solve the equation 3cos x = 8tan x, between Oº and 360°
O [A] 3.99,5.44
[B] 19.5, 160.5
[B] 19.5, 160.5
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