A survey of athletes at a high school is conducted, and the following facts are discovered: 21% of the athletes are football players, 27% are basketball players, and 4% of the athletes play both football and basketball. An athlete is chosen at random from the high school: what is the probability that the athlete is either a football player or a basketball player? Probability =

40% (probability that an athlete is a football player OR a basketball player, but not both) I think this is what its asking, but the wording isn't super clear.

44% (probability an athlete is a football player, basketball player, or both)

Step-by-step explanation:

probability of only football player (21%-4%) plus probability of only basketball player (27-4%)

=17%+23%

=40%

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

answer: group b.

step-by-step explanation: