F(x)=(x-1)^2(x+3)^3(x+1) the zero located at x=1 has a multiplicity of ( blank1 ) and the zero located at x=-3 has a multiplicity of ( blank2 ). The graph of the function will touch, but not cross , the axis at an x-value of (blank3)

blank1: 1,2,3
blank2:1,2,3
blank3: 1 only, -3 and 1 only, -3 only, (-3,-1 and 1),-1 only

option: d is the correct answer.

d) none of the above.

step-by-step explanation:

clearly from the figure attached to the question we could see that there is no shape given. hence without any shape given in the figure and after rotation we can't obtained a square pyramid.

since, to obtain a image we need a proper figure of the pre-image so that it can be transformed.

hence, the correct answer is:

d) none of the above.

step-by-step explanation:

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!