Find two consecutive integers such that one fifth of the first less one-ninth of the second is 3. Pls answer.

35 and 36

Step-by-step explanation:

To solve this problem, we must interpret it line by line;

   let the first number = x

               second number  = x + 1

             x

            (x + 1)

for the "less" ;

         x -  (x + 1) = 3

Multiply through by 45

       45(x) - (45) (x + 1) = 3 x 45

           9x - 5(x + 1) = 135

           9x - 5x -5 = 135

             4x = 135 + 5

              4x = 140

                x = 35

Now, x+1  = 35 + 1 = 36

The consecutive integers are 35 and 36