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Mathematics, 21.10.2020 16:01 irenecupcake4348
Find the absolute maximum and minimum values of the function below. f(x) = x3 − 9x2 + 3, − 3 2 ≤ x ≤ 12 Solution Since f is continuous on − 3 2 , 12 , we can use the Closed Interval Method. f(x) = x3 − 9x2 + 3 f ′(x) = 3x2−18x . Since f ′(x) exists for all x, the only critical numbers of f occur when f ′(x) = , that is, x = 0 or x = . Notice that each of these critical numbers lies in − 3 2 , 12 . The values
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Find the absolute maximum and minimum values of the function below. f(x) = x3 − 9x2 + 3, − 3 2 ≤ x ≤...
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