PLEASE HELP Suppose the football from the example problem (v0 = 20 m/s, 0 = 37.0o) was a punt, and left the punter’s foot at a height of 1.00 m above the ground. How far did the football travel before hitting the ground? Set x0 = 0, y0 = 0.
[Hint: yf = -1 m, and so you will have to use the quadratic formula to find the time.]

i would go with the first one

step-by-step explanation:

hope this

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116