Given that P(x) = ax^2 + bx + 1. P(1) 6 and P(-1) = 2, determine the values of a
and b

Please I Ned help ASAP

a=3

b=2

Step-by-step explanation:

P(x) = ax^2 + bx + 1

P(1)= 6

6= a(1)^2 + b(1) +1

6 = a +b+1

6-1 = a+b

5 = a+b

P(-1) = 2

2 = a( -1)^2 + b(-1) +1

2 = a(1) -b +1

2-1 = a-b

1 = a+b

We have 2 equations and 2 unknowns

Add the two equations together

5 = a+b

1 = a-b

6 = 2a

Divide by 2

6/2 = 2a/2

3 =a

Now find b

5 =a+b

5 =3+b

Subtract 3 from each side

5-3 =3+b-3

2=b

trapezoid

step-by-step explanation:

first i plotted all my points on a grid graph

i made sure all of them were in the correct quadrant

then i saw it was a trapezoid or a quadrilateral