Solve this using the substitution method

-5x+4y=3
X=2y-15

x = 9 , y = 12

Step-by-step explanation:

Solve the following system:

{4 y - 5 x = 3

x = 2 y - 15

Hint: | Perform a substitution.

Substitute x = 2 y - 15 into the first equation:

{4 y - 5 (2 y - 15) = 3

x = 2 y - 15

Hint: | Expand the left-hand side of the equation 4 y - 5 (2 y - 15) = 3.

4 y - 5 (2 y - 15) = 4 y + (75 - 10 y) = 75 - 6 y:

{75 - 6 y = 3

x = 2 y - 15

Hint: | Choose an equation and a variable to solve for.

In the first equation, look to solve for y:

{75 - 6 y = 3

x = 2 y - 15

Hint: | Isolate terms with y to the left-hand side.

Subtract 75 from both sides:

{-6 y = -72

x = 2 y - 15

Hint: | Solve for y.

Divide both sides by -6:

{y = 12

x = 2 y - 15

Hint: | Perform a back substitution.

Substitute y = 12 into the second equation:

{y = 12

x = 9

Hint: | Sort results.

Collect results in alphabetical order:

{x = 9 , y = 12

1/5

step-by-step explanation:

the dice has 6 sides and there is only one 5 in a dice.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2