A committee consists of 8 men and 11 women. In how many ways can a subcommittee of 4 men and 7 women be chosen

23100 ways

Step-by-step explanation:

We have 8 men and 11 women

Number of ways of choosing a subcommittee of 4 men and 7 women

8C4 x 11C7

8!/(8-4)!4! x 11!/(11-7)!7!

= 8!/4!4! x 11!/4!7!

= (40320/24*24) x (39916800/24x5040)

= (40320/576) x (39916800/120960)

=70 x 330

= 23100 ways

We can select a subcommittee of 4 men and 7 women in 23100 ways.

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

-60.75

step-by-step explanation:

just add the numbers then put the negative sign on it