What is the vertex of the graph function y=4x^2+8x-2

vertex = (-1, -6)

Step-by-step explanation:

The function you gave is in the Standard Form : y = aX^2 + bX + c.

So you use the equation x = -b/ 2a    to solve for the x coordinate of your vertex.

Based on your question, a =4, b =8 and c = -2.

So you plug that in and get  x = -8/2(4).   Thus, x value for the vertex is -1.

Now you plug -1 into your original equation to find your y value.

y = 4 (-1)^2 + 8 (-1) -2

So y = -6.  Thus,  your vertex is at pt (-1, -6)

sorry i dont know my friend

b. astronomers