What is the equation of the line that passes through the point (3, 2) and has a slope of - 5/3

y=-5/3+7

Step-by-step explanation:

Point Slope Formula: y=m(x-x1)+y

y=-5/3(x-3)+2

-5/3x+5+2

y=-5/3x+7 (y=mx+b)

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

69.64%

step-by-step explanation: