A particle moves along the x-axis so that at any time t≥0 its position is given by x(t)=12(a−t)2, where a is a positive constant. For what values of t is the particle moving to the right?

For the particle to move to the right, 0 ≤ t ≤ a

Step-by-step explanation:

The particle under motion on the x-axis given by the equation x(t) = 12(a−t)² for t ≥ 0, where a is a positive constant.

To find the values of t for which the particle is moving to the right, this implies that the particle must move along the positive x-axis. This implies that x(t) ≥ 0.

So, to find the value of t for which the particle moves to the right, we solve the inequality x(t) ≥ 0 ⇒ 12(a−t)² ≥ 0

12(a−t)² ≥ 0

(a−t)² ≥ 0

taking square root of both sides, we have

√(a−t)² ≥ √0

(a−t) ≥ 0

a ≥ t ⇒ t ≤ a

So, for the particle to move to the right, 0 ≤ t ≤ a.

24

step-by-step explanation:

the graph shows 30% of students walk. 80 students were questioned, so the number that said they walk is

30% × 80 = 0.30 × 80 = 24