Three six-sided dice are rolled, one red, one green, one blue. How many ways are there to roll the three dice so that two of the dice have the same value and the other die has a value smaller than the common value on the other two?

15

Step-by-step explanation:

Given that:

Three six-sided dices are to be rolled.

The number of ways to have the same value on the two dices is:

{(1,1) ,(2,2) ,(3,3) ,(4,4) , (5, 5 ) ,(6 ,6) }  = 6 ways

Thus; the objective is to determine the number of ways to a get smaller value on the third dice  while the two other dice have the same value.

To get started:

The number of ways for getting a value smaller than 1 = 0

The number of ways for getting a value smaller than 2 = 1

{i.e. (2,2,1)}

The number of ways for getting a value smaller than 3 = 2

{ i.e. (3,3,1) ,(3,3,2) }

The number of ways for getting a value smaller than 4 = 3

{ i.e. (4,4,1) , (4,4,2), (4,4,3)}

The number of ways for getting a value smaller than 5 = 4

{i.e. (5 ,5,1) ,(5,5,2) ,(5,5,3), (5,5,4)}

The number of ways for getting a value smaller than 6  = 5

{i.e. (6,6,1), (6,6,2), (6,6,3), (6,6,4), (6,6,5) }

Thus, the total number of ways = 0 + 1 + 2 + 3 + 4 + 5 = 15

Therefore, the total number of ways getting the value same on two dices and smaller value on the third dice = 15

d) 30 units^2

area of rectangle = l × b

we know,

length = 10 unit

breadth = 3 unit

applying the formula,

= l × b

= 10 × 3

= 30 unit^2

happy to

pls mark as brainliest

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!