Write the equation of a line that is perpendicular to y=-4/3x+9 and goes through (8,-5). Do not use spaces in your answer. Enter fractions as a/b as seen in the given equation. PLEASE HELP ME PLEAE

y=3/4x-11

Step-by-step explanation:

When a line is perpendicular to another line, their slope is the opposite reciprocal of that. So in this case, the slope of the perpendicular line would be positive 3/4. Next, plug in the points (8,-5) in the y=mx+b formula along with the new slope. In conclusion, the new point slope formula is y=3/4x-11.

Hope this helps! :)

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )

a rotation about point l

step-by-step explanation:

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