Please help! Solve each system by elimination. -x-3y- 3z= 16
-6x+3y+2z=-27
4x+6y+4z=-22

I will give brainliest to whoever shows steps!

Step-by-step explanation:

-x-3y-3z=16

x=-3y-3z-16

-6x+3y+2z=-27

6x=3y+2z+27

x=3/6 y + 2/6 z +27/6

x=1/2y+1/3z+9/2

4x+6y+4z=-22

4x=-6y-4z-22

x= -6/4y -4/4 z -22/4

x=-3/2y -z-11/2

(x, y, z) = (2,-3,-3)

Step-by-step explanation: 4x+6y+4z = -22 Divide both sides by = 2x + 3y+2z= -11

To solve the system , rewrite it as two systems each consisting of two equations.

1) {-x-3y-3z = 16} {-6x+3y+2z = -27}

2) {-x-3y-3z=16} {2x+3y+2z=-11}

Solve the system of equations

1) -7x-z=-11

2)x-z=5

Write as a system of equations

{-7z-z=-11} {x-z=5}

Solve the system of equations

z = -3

x= 2

Substitute the given value of z, x into the equation : -x-3y-3z = 16

-2-3y-3x(-3)= 16

Solve for Y

y= -3

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680