To find the product of 3
7
×
5
9
, Cameron simplified
3
7
to
1
7
and then multiplied the fractions
1
7
and
5
9
to find the product
5
63
. What is Cameron's error?

Cameron divided a factor in one of the numerators by the GCF but did not divide a factor in one of the denominators by the GCF. He should have simplified
5
9
to and multiplied
1
7
and to find the product .
please i need help.

we have the parent function given by,

1. the function is translated 5 units to the left.

so, we get,   becomes

2. the function is translated 5 units to the right.

so, we get,   becomes

3. the function is translated 5 units upwards.

so, we get,   becomes

4. the function is translated 5 units downwards.

so, we get,   becomes

5. the function is reflected across x-axis.

so, we get,   becomes

6. the function is reflected across y-axis.

so, we get,   becomes .

step-by-step explanation:

mark brainliest.

2

step-by-step explanation:

yes

step-by-step explanation:

so of course you want to start by plugging the 5 in which goes to 7(5)+3(5)=50 because 7*5=35 and 3*5=15 and then add them together, then plug in the 5 to the other equation as well 9(5)+5=50 because 9*5= 45 and then add 5 and so yes they are equivalent.