Look at the rectangle and the square: A rectangle PQRS and square LMNO are drawn side by side. The length SR of the rectangle is labeled as 16 inches, and the width QR is labeled as 8 inches. The side LM of the square is labeled as 8 inches
Ada says that the length of diagonal SQ is two times the length of diagonal OM.

Is Ada correct? Justify your answer and show all your work. Your work should state the theorem you used to find the lengths of the diagonals. (10 points)
Pls answer ASAP, will give Brainlist

Ada was incorrect

Step-by-step explanation:

The length of SQ is

16^2 + 8^2 = SQ^2

256 + 64 + SQ^2

256 + 64 =320

The square root of SQ^2 is SQ and the square root of 320 is approximately 17.8885

The length of OM is

8^2 + 8^2 = OM^2

64 + 64 = OM^2 

64 + 64 + 128

The square root of OM^2 is OM and the square root of 128 is approximately 11.3137

Half of 17.8885 is approximately 8.9442 

So Ada was incorrect the length of OM is not half the length of SQ

-sorry this is probably to late

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3