Need answers to number 11 and step by step please
Much appreciated thank you

∠1 = 43

∠2 = 17

∠3 = 120

∠4 = 60

∠5 = 60

∠6 = 60

∠7 = 17

∠8 = 120

∠9 = 43

Step-by-step explanation:

11) ΔABC is isosceles triangle. In isosceles triangle two sides are equal and angles opposite to two sides are equal  {Isosceles triangle property}

∠C = ∠A

      9x - 47 =  4x + 3

9x - 4x - 47 = 3

     5x - 47 = 3

           5x = 3 + 47

           5x = 50

              x = 50/5

x = 10

∠1 = 4x +3 = 4*10 + 3 = 40 + 3

∠1 = 43

∠9 = 43

ΔDBE is equilateral. So all angles are equal in equilateral.

Each angel in equilateral triangle = 180÷ 3 = 60

∠4 = ∠5 = ∠6 = 60

∠3 + ∠4 = 180     {linear pair}

∠3 + 60 = 180

      ∠3 = 180 - 60

 ∠3 = 120

∠6 + ∠8 = 180    {linear pair}

60 + ∠8 = 180

      ∠8   = 180 - 60

  ∠8 = 120

In ΔABD,

∠1 + ∠2 + ∠3 = 180            {angle sum property of triangle}

43 + ∠2 + 120 = 180

     ∠2 + 163   = 180

             ∠2     = 180 - 163

∠2 = 17

In ΔBEC,

∠7 +∠8 +∠9 = 180   {angle sum property of triangle}

∠7 + 120 + 43 = 180

    ∠7   + 163 = 180

               ∠7 = 180 - 163

              ∠7 = 17

multiplication is multiplication.   it might feel harder depending on what level of math you are in, but generally it will be the same old stuff, while implementing some new concepts and methods of solving work.

it is rigid.; it is isometric. ; the size is preserved.

step-by-step explanation:

a translation is called an isometry; these are transformations that preserve congruence between pre-images and images.

they are also called rigid transformations, as the only thing that can happen to a pre-image is that it is moved or turned, not stretched or shrunk.

since congruence is preserved, the size is preserved.