I need help, this is geometry

∠P = 39º

∠Q=120º

∠R = 21º

Step-by-step explanation:

m∠P+m∠Q+m∠R=180º (sum of ∠s in a triangle)

2x-3+6x-6+x=180º (substitution)

9x-9=180º (algebra)

9x=189º (algebra)

x=21º (algebra) (this is ∠R)

(2x-3)=39º (algebra) (this is ∠P)

6x-6=120º (algebra) (this is ∠Q)

∠R = 21°

∠Q = 120°

∠P = 39°

Step-by-step explanation:

Step 1:

6x - 6° + 2x - 3° + x = 180°        Sum of a Δ

Step 2:

9x - 9° = 180°         Combine Like Terms

Step 3:

9x = 189°        Add 9 on both sides

Step 4:

x = 189° ÷ 9       Divide

Step 5:

x = 21°

Step 6:

2 ( 21 ) - 3 = ∠P = 39°

Step 7:

6 ( 21 ) - 6 = ∠Q = 126°

Step 8:

∠R = 21°

∠R = 21°

∠Q = 120°

∠P = 39°

Hope This Helps :)

answer: r there any options?

step-by-step explanation:

ιт ιѕ 6/23

step-by-step explanation:

нσρє ι ¢συℓ∂ нєℓρ!