three numbers have a sum of 112. The first number is twice the second, and the third number is twice the first. What is the smallest of the three numbers?

The second number is the smallest of the three numbers with

value n = 16.

Step-by-step explanation:

Let n represent the second number, then the first number is 2n and the third number is 4n.

so

Solving for n

As n = 16 is the second number.

The first number = 2n = 2(16) = 32

The third number = 4n = 4(16) = 64

Therefore, the second number is the smallest of the three numbers with value n = 16.

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."