Find the distance from A(15,21) to the line 5x +2y=4. Round your answer to the nearest tenth

The distance from a point to a line is

distance(ax+by+c=0,(x0,y0)) = abs(ax0+by0+c)/sqrt(a^2+b^2)

So first convert the formula for the line to standard form

5x+2y=4

5x+2y-4=0

a=5, b=2, c=-4, x0=15, y0=-21

Step-by-step explanation:

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option