2(x + 1 ) - 3(x + 5) ≥ 0
plss help

Inequality form x less than or equal to -13

Step-by-step explanation

x ≤ -13

Step-by-step explanation:

2(x + 1) - 3(x + 5) ≥ 0

Distribute the 2

(2 × x) + (2 × 1)

2x + 2 - 3(x + 5) ≥ 0

Distribute the -3

(-3 × x) + (-3 × 5)

2x + 2 - 3x + (-15) ≥ 0

2x + 2 - 3x - 15 ≥ 0

Combine like terms

2x - 3x + 2 - 15 ≥ 0

-x + (-13) ≥ 0

-x - 13 ≥ 0

   +13    +13

-x ≥ 13

Divide both sides by -1 and flip the sign

x ≤ -13

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3