Write an equation of the line that passes through the given point and is perpendicular to the graph of the given equation. SHOW ALL STEPS PLEASE HURRY I'M BEING TIMED 1.(2, -1); y = -2x + 1

2.(5, 7); y =1/3x + 2

3.(3, -6); x + y = -4

4.(-9, 3); 3x + y = 5

5.(-8, 3); y+4 = -2/3 (x - 2)

6.(0, -5); x - 6y = -2
CAN SOMEONE PLEASE ANSWER THE QUESTION PLEASE

v: l•w•h÷2.

v: 20•6•8 ÷2

v: 960÷2

v: 480

it's d

step-by-step explanation:

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b

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step-by-step explanation:

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