PLEASEEE HELP FAST 1. During which parts of the graph does Arthur’s distance from home decrease?
2. When is Arthur waiting for bagels? Explain how you know.
3. If Arthur’s pace had not been constant after leaving the bagel shop, which part of the graph would change? Explain how that part of the graph would change.

1. During part 2. The y-axis (line going up) represents his distance. At part 1, his distance stays the same because he is sitting in the park. At part 2 we see the line go down, which means his distance from home is decreasing.

2.At part 3. His distance stays the same, which represents him waiting in line. We know this because the line stays at the same distance and the time increases(this is the x-axis)

3. There would be another part of the graph. If he had stopped again, there would have been another straight line with the distance the same and the time increasing.  

Step-by-step explanation:

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

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step-by-step explanation:

answer:

a=9

step-by-step explanation: lmk if you need a explanation