Use a graphing calculator to sketch the graph of the quadratic equation, and then state the domain and rangey=x^2+2x+2 y = x squared + 2 x + 2
a.
D: all real numbers
R: y less-than-or-equal-to 2
c.
D: x greater-than-or-equal-to 1
R: y greater-than-or-equal-to 2
b.
D: all real numbers
R: y less-than-or-equal-to 1
d.
D: all real numbers
R: y greater-than-or-equal-to 1

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

y= 2x+7

changed to y= 5x +7

as slope is increased from 2 to 5

therefore it would be less steeper

so, option d) is correct

  answer:

  write 548 as 500 + 40 + 8. multiply each addend by 5. then add the three products to get 2,740.