A parallelogram with coordinates A (-2,3), B (3,3), C (4,6), and D(-1,6) is the first rotated 90 degrees clockwise and then translated 4 units left and 2 units down to form quadrilateral A'B'C'D what is the distance, in units between point C' and point D' in the resulting figure

Given:

The vertices of a parallelogram are A (-2,3), B (3,3), C (4,6), and D(-1,6).

It is first rotated 90 degrees clockwise and then translated 4 units left and 2 units down to form quadrilateral A'B'C'D.

To find:

The distance between C' and D'.

Solution:

If a figure rotated 90 degrees clockwise, then

If figure translated 4 units left and 2 units down, then

Distance formula:

Distance between C'(2,-6) and D'(2,-1) is

Therefore, the distance between C'D' is 5 units.

moderators are

step-by-step explanation:

a'(12.5,11.25)

slope=(y1-y2)/(x1-x2)