A) The sixth term of an AP is twice the 3rd term and the first term is 3. Find the common difference and the 10th term

Step-by-step explanation:

The nth term of an AP is expressed as;

Tn = a+(n-1)d

a is the first term

n is the number of terms

d is the common difference

Sixth term

T6 = a+(6-1)d

T6 = a+5d

Third term;

T3 = a+(3-1)d

T3 = a+2d

If the sixth term of an AP is twice the 3rd term, then

a+5d = 2(a+2d)

a+5d = 2a+4d

Given a = 3

3+5d = 2(3)+4d

5d-4d = 6-3

d = 3

Common difference is 3

For the 10th term

T10 = a+9d

T10 = 3+9(3)

T10 = 3+27

T10 = 30

Hence the tenth term is 30

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

step-by-step explanation:

formula

x = x1 + p/w(x2 - x1)

let the line segment ab with a(x1,y1) and b(x2,y2)

a point(x,y) divide ab in the ratio, 2: 3 the x coordinate can be written as

x = x1 + p/w(x2 - x1)

here p=2 and w = 2+3

therefore,

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

similarly y coordinate y = y1 + 2/5(y2 - y1)