Find the integers m and n such that (m+n√2)(1-√2)²=-2+2√2

m = n = 2

Step-by-step explanation:

(m + n√2)(1 - √2)² = -2 + 2√2

(m + n√2)(1 - 2√2 + 2) = -2 + 2√2

(m + n√2)(3 - 2√2) = -2 + 2√2

3m - 2m√2 + 3n√2 - 4n = - 2 + 2√2

(3n - 2m)√2 + 3m - 4n = 2√2 - 2

3n - 2m = 2

4n - 3m = 2

3n - 2m = 4n - 3m

n = m

4n - 3n = 2

n = 2

m = 2

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.

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step-by-step explanation:

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