what is the remainder when the sum of the smallest and second smallest prime numbers is divided my the third smallest prime number Can I also get an explanation so I know how it's done? Thanks :)

he earned 78.75 in interest.

step-by-step explanation:

look in attachments

step-by-step explanation:

a = (-2, 0)

b= (-4, 0)

c = (-5,2)

d = (-1,2)

step-by-step explanation:

consider the parallelogram shown in the attached image.

in the parallelogram hijk, the length of hk is given as,

from the properties of parallelogram we know that the opposite sides of a parallelogram are parallel to each other and are equal in measure.

therefore, the length of the side ij must be equal to the length of the side hk and that is .

hence, the expression for the length of ij confirms that hijk is a parallelogram.

a+b=c is your answer