The volume of a cylinder is 75 cubic centimeters and its radius is 2 centimeters. Which is closest to the height of the cylinder?(I NEED HELP FAST)

Step-by-step explanation:

3cm

Step-by-step explanation:

the sphere and the cylinder have the same height because of this the height of the cylinder is equal to the diameter of the sphere the diameter of the sphere is 2*7=14 cm, so the height of the cylinder is also 14 cm the radius of the cylinder is 7 cmV=∏*r^2*hV=3.14159*7^2*14V=3.14159*49*14V=3.14159*686V=2155.13074 cubic cm, or...V=(22/7)(7^2)(14)       (22/7 is an approximation for pi)V=(22/7)(49)(14)V=(22)(7)(14)V=(22)(98)V=2156 cubic cm

for this case we have the following expression:

to solve, we rewrite the expression as:

we apply double c and we have:

thus, the quotient is 48.

so, patel found a wrong ratio and the multiplication was incorrect.

option d

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer