In ΔBCD, \text{m}\angle B = (8x+9)^{\circ}m∠B=(8x+9) ∘ , \text{m}\angle C = (5x+5)^{\circ}m∠C=(5x+5) ∘ , and \text{m}\angle D = (2x+1)^{\circ}m∠D=(2x+1) ∘ . What is the value of x?x?

x = 11

Step-by-step explanation:

The sum of angles in a triangle = 180°

From the question

In ΔBCD

m∠B=(8x+9) ∘

m∠C=(5x+5) ∘

m∠D=(2x+1) ∘

What is the value of x?

x is calculated as:

m∠B + m∠C + m∠D = 180°

(8x + 9)° + (5x + 5)° + (2x + 1)° = 180°

8x + 9 + 5x + 5 + 2x + 1 = 180°

Collect like terms

8x + 5x + 2x + 9 + 5 + 1 = 180°

15x + 15 = 180°

15x = 180° - 15°

15x = 165

x = 165/15

x = 11

this is a very good question

step-by-step explanation:

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