A school district held a meeting for all its physical education teachers. The number of women attending was 5 more than twice the number of men attending. A total of 53 teachers attended the meeting. Which system of equations could be used to find w, the number of women, and m, the number of men, at this meeting?

Step-by-step explanation:

From the given information:

let the number of women be w;&

the number of men be equal to = m

SO;  if the school district held a meeting for all its physical education teachers, both the number of women and men must be equal to the total number of teachers attending the meeting.

w + m = 53     (1)

However, if the number of women was 5 more than twice the number of men;

Then:

2m + 5 = w     Let that be equation (2)

Then, we can now replace the value of w in equation (2) into equation (1).

w  + m = 53

(2m + 5) + m = 53

3m + 5 = 53

3m = 53 - 5

3m = 48

m = 48/3

m = 16

From equation (1)

w + m = 53

w + 16 = 53

w = 53 -16

w = 37

Therefore, the number of women w = 37 and the number of men = 16

b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5