What is the base of the exponent in the function fx=3(3/8)^2

by definition, an exponential function with base c is defined by h (x) = ac^x  

where a ≠0, c > 0 , b ≠1, and x is any real number.

The base, c, is a constant and the exponent, x, is a variable.  

so if we have  f(x)=3(3\8)^2x, this equivalent to f(x)=3(3\8)^y(x),  

where y (x)=2x,  

therefore, the base is  3/8, and the variable is the function y (x)=2x,  it is 4

Step-by-step explanation:

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17