Select from the drop-down menus to correctly complete the proof. To prove that 4π is irrational, assume the product is rational and set it equal to ab, where b is not equal to 0: 4π=ab. Isolating π gives π=a4b. The right side of the equation is Choose... . Because the left side of the equation is Choose... , this is a contradiction. Therefore, the assumption is wrong, and the number 4πis Choose... .

d

step-by-step explanation:

by observation, we can see that the the graph is simply the graph of y = |x| that has been shifted 4 units downwards and 3 units to the left.

we can recognize in choice d :

y = | x + 3 |   - 4 (rewriting in general form)

y = | x - (- 3) |   - 4

the "-4 " term means   that the graph has been shifted by 4 units in the negative y direction

the "-3 " term means   that the graph has been shifted by 3 units in the negative x direction

this matches our observation of the graph described above.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

i believe it's a.

i'm not sure on this one, most likely correct.